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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2021

PhysicsEasysingle choice

De-Broglie wavelength associated with an electron accelerated through a potential difference ' $V$ ' is ' $λ$ '. When the accelerating potential is increased to ' $4 V$ ', de-Broglie wavelength.

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Answer:

Solution:

De-Broglie wavelength, $λ = \frac{1.228}{V} (nm)$ If $V$ is increased to $4 V$ , then $λ$ will become $\frac{1}{4}$ times or $\frac{1}{2}$ times.

Stream:MHT_CETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2021

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