Physics - Modern Physics Question with Solution | TestHub

Given,$m=1 g={10}^{-\mathrm{3 }}\mathrm{k}\mathrm{g}$

Energy,$E=m{c}^2$

$\therefore$Energy equivalent$={10}^{-3}\times {\left(3\times {10}^8\right)}^2$

$\left(\because c=3\times {10}^8\mathrm{ m}{\mathrm{ s}}^{-1}\right)$

$=9\times {10}^{13} J$