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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The total energy of an electron revolving in the second orbit of a hydrogen atom is

Answer:

Solution:

$E = \frac{- 13.6}{n^{2}} eV$

For $n = 2, E = \frac{- 13.6}{2^{2}} = - 3.4 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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