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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If the ratio of the radius of a nucleus with $61$ neutrons to that of helium nucleus is $3$ , then the atomic number of this nucleus is

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Answer:

Solution:

The radius is directly proportional to $\frac{1}{3}$ power of mass number, i.e., $R \propto A^{\frac{1}{3}}$

Or $\frac{A_{1}}{A_{2}} = {(\frac{R_{1}}{R_{2}})}^{3} = {(\frac{1}{3})}^{3} = \frac{1}{27}$

$\Rightarrow \frac{A_{2}}{A_{1}} = 27$

$\Rightarrow A_{2} = A_{1} \times 27$

$= 4 \times 27 = 108$

$\Rightarrow Z_{2} = A_{2} - 61$

$= 108 - 61 = 47$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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