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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

Half-lives of two radioactive substances $A$ and $B$ are respectively $20 \min$ . and $40 \min$ . Initially, the samples of A and B have equal number of nuclei. After $80 min ,$ the ratio of the remaining nuclei of $A$ and $B$ is

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Answer:

Solution:

Use, $N = \frac{N_{0}}{2^{n}}$

$\Rightarrow N_{A} = \frac{N_{0}}{2^{\frac{80}{20}}} = \frac{N_{0}}{2^{4}}$

$N_{B} = \frac{N}{2^{\frac{80}{40}}} = \frac{N_{0}}{2^{2}}$

$\Rightarrow \frac{N_{A}}{N_{B}} = \frac{1}{4}$

$\Rightarrow N_{A} : N_{B} = 1 : 4$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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