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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

In a radioactive material, the activity at time $t_{1}$ is $R_{1}$ and at a later time $t_{2}$ , it is $R_{2}$ . If the decay constant of the material is $λ$ , then

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Answer:

Solution:

According to activity law, R = R₀e^–λt

∴ R₁= R₀e^–λt^₁and R₂= R₀e^–λt^₂

$∴ \frac{R_{1}}{R_{2}} = \frac{R_{0} e^{- λ t_{1}}}{R_{0} e^{- λ t_{2}}} = e^{- λ t_{1}} e^{λ t_{2}} = e^{- λ (t_{1} - t_{2})}$

or $R_{1} = R_{2} e^{- λ (t_{1} - t_{2})}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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