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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

The stopping potential as a function of frequency of incident radiation is plotted for two different photoelectric surfaces $A$ and $B$ . The graphs show that the work function of $A$ is

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Answer:

Solution:

We know that $E = w + k E$

$h v = h v_{0} + e V_{0}$

$v_{0} = \frac{h v}{e} - \frac{h v_{0}}{e}$

From graph, we can see that $v_{0}$ is less for $A$ and greater for $B$ .

Hence work function of $A$ is less than $B$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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