If the de-Broglie wavelength is λ 0 for protons accelerated through 100 V , then the de-Broglie wavelength for alpha particles accelerated through the same voltage will be

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De-Broglie wavelength is λ = h 2 m K = h 2 m q V Therefore, de-Broglie wavelength for protons. λ 0 = h 2 m p e V 0 and de-Broglie wavelength for alpha particles λ ′ = h 2 4 m p 2 e V 0 λ 0 λ ′ = 8 = 2 2 λ ′ = λ 0 2 2

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