The half-life of At 215 is 100 μs . The time taken for the radioactivity of a sample of At 215 to decay to 1 1 6 th of its initial value is

If R is activity of radioactive substance after n half lives then R = R 0 1 2 n ; R 0 16 = R 0 1 2 n ∴ n = 4 ; t = nT 1 / 2 = 4 × 100 = 400 μ s

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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

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The half-life of ${}^{215}{At}$ is $100 μs$ . The time taken for the radioactivity of a sample of ${}^{215}{At}$ to decay to ${(\frac{1}{16})}^{th}$ of its initial value is

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Solution:

If $R$ is activity of radioactive substance after $n$ half lives then

$R = R_{0} {(\frac{1}{2})}^{n}; \frac{R_{0}}{16} = R_{0} {(\frac{1}{2})}^{n}$

$∴ n = 4; t = {nT}_{1 / 2} = 4 \times 100 = 400 μ s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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