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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

The mass of a37Linucleus is0.042 uless than the sum of the masses of all its nucleons. The binding energy per nucleon of37Linucleus is nearly

Options:

Answer:
B
Solution:

For37Linucleus,

Mass defect,ΔM=0.042 u

∵1 u= 931.5 MeV c-2

∴ Δ M = 0.042×931.5 MeV c-2

=39.1 MeV c-2

Binding energy,Eb=ΔMc2

= 3 9 · 1 MeV c 2 c 2

=39.1 MeV

Binding energy per nucleon,⁡E⁡bn=E⁡bA⁡=39·1 MeV7

≈5·6 MeV

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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