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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

An electron is at ground state of the $H$ atom. The minimum energy required to excite the $H$ atom into the second excited state is

Options:

Answer:

Solution:

According to question, for an electron to jump from first excited state to second, He

energy required is, $Δ E = E_{3} - E_{1}$

$= - \frac{13.6}{{(3)}^{2}} - (- 13.6)$

[ $∵$ Energy of excited $2^{n d}$ excited state, $E_{3} = - \frac{13.6}{9}]$

$\Rightarrow Δ E = - 1.5 + 13.6 = 12.1 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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