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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

Consider the nuclear reactionX200→A110+B80.If the binding energy per nucleon forX,AandBare7.4 MeV,8.2 MeVand8.1 MeV, respectively, then the energy released in the reaction is

Options:

Answer:
A
Solution:

For X : binding energy=200×7.4=1480 MeV

For A : binding energy=110×8.2=902 MeV

For B : binding energy=80×8.1=648 MeV

∴Energy released=902+648-1480

=1550-1480

=70 MeV

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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