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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The binding energy of deuteron is $2.2 MeV$ and that of $_{2}^{4} He$ is $28 MeV .$ If two deuterons are fused to form one $_{2}^{4} He$ , then the energy released is

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Answer:

Solution:

$_{1}^{2} H +_{1}^{2} H ⟶_{2}^{4} He + energy$
Energy released $= B . E .$ of $_{2}^{4} H e - 2 (B . E .$ of $_{1}^{2} H)$
$= 28 - 2 (2.2) = 28 - 4.4 = 23.6 MeV .$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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