The kinetic energy of the most energetic photoelectrons emitted from a metal surface is doubled when the wavelength of the incident radiation is reduced from $λ_{1}$ to $λ_{2}$ . The work function of the metal is
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Answer:
A
Solution:
$k = \frac{hc}{λ_{1}} - ϕ$ and $2 k = \frac{hc}{λ_{2}} - ϕ$

Question

The kinetic energy of the most energetic photoelectrons emitted from a metal surface is doubled when the wavelength of the incident radiation is reduced from $λ_{1}$ to $λ_{2}$ . The work function of the metal is

Options:

Answer:

A

Solution:

$k = \frac{hc}{λ_{1}} - ϕ$ and $2 k = \frac{hc}{λ_{2}} - ϕ$

TestHub · Accepted Answer

k = hc λ 1 - ϕ and 2 k = hc λ 2 - ϕ

Physics - Modern Physics Question with Solution | TestHub

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