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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2020

PhysicsEasysingle choice

The de-Broglie wavelength of a neutron at $927 ° C$ is $λ$ . What will be its wavelength at $27 ° C$ ?

Options:

Answer:

Solution:

We know that, $λ = \frac{h}{\sqrt{2 m k T}}$ ;

So, $λ \propto \frac{1}{\sqrt{T}}$

$∴ \frac{λ_{27}}{λ_{927}} = \sqrt{\frac{927 + 273}{27 + 273}} = 2$

or $λ_{27} = 2 λ_{927} = 2 λ$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2020

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