Given that a photon of light of wavelength 10,000 Å has an energy equal to 1.23 eV. When light of wavelength 5000 Å and intensity I 0 falls on a photoelectric cell, the surface current is 0.40 × 10 -

Question

Given that a photon of light of wavelength 10,000 Å has an energy equal to 1.23 eV. When light of wavelength 5000 Å and intensity I 0 falls on a photoelectric cell, the surface current is 0.40 × 10 - 6 A and the stopping potential is 1.36 V, then the work function is

TestHub · Accepted Answer

E = h c λ or E ∝ 1 λ ∴ E 2 E 1 = λ 1 λ 2 or E 2 = E 1 × λ 1 λ 2 = 1.23 × 10,000 5,000 = 2.46 e V Now, h v - ϕ 0 = 1 2 m v m a x 2 = e V s or ϕ 0 = h v 2 - e V s = E 2 - e V s = 2.46 - 1.36 = 1.10 e V

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