If the work function for a certain metal is 3.2 × 10 - 19 J and it is illuminated with light of frequency ν = 8 × 10 14 Hz , the maximum kinetic energy of the photoelectron would be

Maximum KE = h v - ϕ 0 = 6.63 × 10 - 34 × 8 × 10 14 - 3.2 × 10 - 19 = 2.1 × 10 - 19 J

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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

If the work function for a certain metal is $3.2 \times 10^{- 19} J$ and it is illuminated with light of frequency $ν = 8 \times 10^{14} Hz$ , the maximum kinetic energy of the photoelectron would be

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Answer:

Solution:

Maximum KE $= h v - ϕ_{0}$

$= 6.63 \times 10^{- 34} \times 8 \times 10^{14} - 3.2 \times 10^{- 19}$

$= 2.1 \times 10^{- 19} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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