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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020

PhysicsEasysingle choice

The half-life of Radioactive substance is $20 \min$ . The approximate time interval ( $t_{2} - t_{1}$ ) between the time $t_{2}$ when $\frac{2}{3}$ of it has decayed and time $t_{1}$ when $\frac{1}{3}$ of it had decayed is

Options:

Answer:

Solution:

$N_{1} = N_{0} - \frac{1}{3} N_{0} = \frac{2}{3} N_{0}$

$N_{2} = N_{0} - \frac{2}{3} N_{0} = \frac{1}{3} N_{0}$

$∴ \frac{N_{2}}{N_{1}} = {(\frac{1}{2})}^{n}$

$n = 1$

$∴ t_{2} - t_{1} = o n e h a l f - l i f e = 20 m i n$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2020

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