Physics - Modern Physics Question with Solution | TestHub

When light waves of differing frequencies are made incident on the same surface, the stopping potential ($V_s$) differ as is evidenced from Einstein's photoelectric equation given by

$hv-h{v}_0=e{V}_s$

where$h$is Planck's constant,$v,v_0$the frequencies and$e$the charge.



Hence,${ V}_s=\frac{hv}{e}-\frac{hv}{e}$...(i)

Comparing Eq. (i) with straight line equation

$y=mx+c$

Slope$m=\frac{h}{e}$

$Where h=6.6\times {10}^{-34} Js, e=1.6\times {10}^{-19} C.$

$\therefore m=\frac{6.6\times {10}^{-34}}{1.6\times {10}^{-19}}=4.125\times {10}^{-15}$