The graph which shows the variation of ( λ 2 1 ) and its kinetic energy, E is (where λ is de Broglie wavelength of a free particle):NEET 2024

de-Broglie wavelength λ = P h = m v h = 2 m E h where E = 2 1 m v 2 Squaring both sides, λ 2 = 4 m 2 E h 2 ⇒ λ 2 1 = (constant) E Graph passes through origin with constant slope.

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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2024

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The graph which shows the variation of $(\frac{1}{λ ^{2}})$ and its kinetic energy, $E$ is (where $λ$ is de Broglie wavelength of a free particle):NEET 2024

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Solution:

de-Broglie wavelength $λ = \frac{h}{P} = \frac{h}{m v} = \frac{h}{2 m E}$ where $E = \frac{1}{2} m v^{2}$ Squaring both sides, $λ^{2} = \frac{h ^{2}}{4 m ^{2} E} \Rightarrow \frac{1}{λ ^{2}} = (constant) E$ Graph passes through origin with constant slope.

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2024

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