What is the age of an ancient wooden piece if it is known that the specific activity of C 14 nuclide in its amounts is 3/5 of that in freshly grown trees? Given the half of C nuclide is 5570 yr .

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Here, \mathrm{N}_{0}=\frac{3}{5} N_{0} e^{-\lambda t}$ \begin{array}{l}e \lambda^{t}=\frac{5}{3} \ 	herefore \quad \log e^{\lambda t}=\log _{e} \frac{5}{3} 	ext { or } \lambda t=\log _{e} \frac{5}{3} \ 	ext { or } \mathrm{t}=\frac{1}{\lambda} \log _{e} \frac{5}{3} \ =\frac{T}{0.693} 	imes 0.5 \quad\left(\because T=\frac{0.693}{\lambda}ight) \ =\frac{5570 	imes 0.5}{0.693} y r=4018.7 y r s\end{array}

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