The ionization energy of hydrogen atom is $13.6 e V$ . Hydrogen atoms in the ground state are excited by electromagnetic radiation of energy $12.1 e V$ . How many spectral lines will be emitted by the hydrogen atoms
Options:
Answer:
C
Solution:
Number of spectral lines $= \frac{n (n - 1)}{2} = \frac{3 (3 - 1)}{2} = 3$

Question

The ionization energy of hydrogen atom is $13.6 e V$ . Hydrogen atoms in the ground state are excited by electromagnetic radiation of energy $12.1 e V$ . How many spectral lines will be emitted by the hydrogen atoms

Options:

Answer:

C

Solution:

Number of spectral lines $= \frac{n (n - 1)}{2} = \frac{3 (3 - 1)}{2} = 3$

TestHub · Accepted Answer

Number of spectral lines = n ( n - 1 ) 2 = 3 ( 3 - 1 ) 2 = 3

Physics - Modern Physics Question with Solution | TestHub

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