Physics - Modern Physics Question with Solution | TestHub

Momentum of striking electrons$p=\frac{h}{ \lambda }$

$\therefore$Kinetic energy of striking electrons

$K=\frac{p^2}{2m}=\frac{h^2}{2m{\lambda }^2}$

This is also, maximum energy of X-ray photons.

Therefore,$\frac{hc}{ {\lambda }_0}=\frac{h^2}{2m{\lambda }^2}$

Or${\lambda }_0=\frac{2m{\lambda }^{2}c}{h}$