Physics - Modern Physics Question with Solution | TestHub

Let, t = 0, M₀= 10 g

$t=2\tau =2\left(\frac{1}{\lambda }\right)\left(\text{given}\right)$

$\text{Then from,}M=M_0{e}^{-\lambda t}=10e^{-\lambda \left(\frac{2}{\lambda }\right)}$

$=10{\left(\frac{1}{e}\right)}^2=1·35\text{g.}$