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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2025

PhysicsMediumsingle choice

The frequency of revolution of the electron in Bohr's orbit varies with $n$ , the principal quantum number as

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Solution:

$f = \frac{v}{2 π r} = (\frac{V _{0}}{n}) (\frac{1}{2 π r _{0} n ^{2}}) f = \frac{V _{0}}{2 π r _{0}} = (\frac{1}{n ^{3}}) = f_{0} (\frac{1}{n ^{3}})$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2025

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