Physics - Modern Physics Question with Solution | TestHub

Wavelength of a particle is given by $\lambda =\frac{h}{p}$ where $h$ is Planck's constant. and wavelength of an electron is given by $\begin{array}{rl}{\lambda }_e& =\frac{h}{p_e}\\ \lambda & ={\lambda }_e\\ p& =p_e\\ mv& =m_e{y}_e\\ y& =\frac{m_e{v}_e}{m}\end{array}$ So, Putting the undergiven data, we get $\begin{array}{rl}& m_e=9.1\times 10^{-31}\mathrm{kg},v_e=3\times 10^6\mathrm{m}/\mathrm{s}\\ & m=1\mathrm{mg}=1\times 10^{-6}\mathrm{kg}\\ & y=\frac{9.1\times 10^{-31}\times 3\times 10^6}{1\times 10^{-6}}\\ & =2.7\times 10^{-18}{\mathrm{ms}}^{-1}\end{array}$