If the rate of emission of energy from a star is 2.7 × 1 0 36 J / s e c , the rate of loss of mass in the star will be

E = m c 2 ∴ m = E c 2 = 2.7 × 1 0 36 9 × 1 0 16 = 27 × 1 0 35 9 × 1 0 16 = 3 × 1 0 19 k g / s e c

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

If the rate of emission of energy from a star is $2.7 \times 1 0^{36} J / s e c$ , the rate of loss of mass in the star will be

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Answer:

Solution:

$E = m c^{2}$

$∴ m = \frac{E}{c^{2}} = \frac{2.7 \times 1 0^{36}}{9 \times 1 0^{16}}$

$= \frac{27 \times 1 0^{35}}{9 \times 1 0^{16}} = 3 \times 1 0^{19} k g / s e c$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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