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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

Consider the nuclear reactionX200→A110+B80+10n1. If the binding energy per nucleon forX,AandBare7.4 MeV,8.2 MeVand8.1 MeVrespectively, then the energy released in the reaction -

Options:

Answer:
A
Solution:

For X: energyE1=200×7.4=1480MeV

For A: energyE2=110×8.2=902MeV

For B: energyE3=80×8.1=648MeV

Energy ReleasedE=E1+E2+E3

E=902+648-1480=70MeV

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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