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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is

Answer:

Solution:

According to Bohr's theroy

$m v r = \frac{n h}{2 π}$

$2 π r = \frac{n h}{m v}$

$2 π r = n λ$

For n=1, $λ = 2 π r$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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