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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minQB

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The ratio of the de Broglie wavelength of a proton and an alpha particle will be 1 : 2 if their:

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Solution:

$\frac{λ _{p}}{λ _{α}} = \frac{p _{α}}{p _{p}} = \frac{1}{2} \Rightarrow p_{p} = 2 p_{α}$ . With $m_{α} = 4 m_{p} : \frac{v _{p}}{v _{α}} = \frac{p _{p} / m _{p}}{p _{α} / m _{α}} = 2 \times 4 = 8 : 1$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: QB

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