Electron in Hydrogen atom first jumps from third excited state to second excited state and then from second excited state to first excited state. The ratio of the wavelengths λ 1 : λ 2 emitted in

Question

Electron in Hydrogen atom first jumps from third excited state to second excited state and then from second excited state to first excited state. The ratio of the wavelengths λ 1 ​ : λ 2 ​ emitted in the two cases respectively is

TestHub · Accepted Answer

λ 1 ​ 1 ​ = R ( 2 2 1 ​ − 3 2 1 ​ ) = R ( 4 1 ​ − 9 1 ​ ) = R ( 36 5 ​ ) λ 2 ​ 1 ​ = R ( 1 − 2 2 1 ​ ) = R ( 4 3 ​ ) λ 2 ​ λ 1 ​ ​ = 4 3 ​ × 5 36 ​ = 5 27 ​

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