If an electron has energy such that it's De Broglie wavelength is 5500 A ∘ , then the energy value of that electron is h = 6.626 × 10 - 34 J s , m e = 9.1 × 10 31 kg .

λ = h p a n d p 2 2 m = E p = h λ = 2 m E ⇒ E = h 2 2 m λ 2 Substitutions the given values E = 8 × 10 - 25 J

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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

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If an electron has energy such that it's De Broglie wavelength is $5500 \overset{\circ}{A}$ , then the energy value of that electron is $(h = 6.626 \times 10^{- 34} J s, m_{e} = 9.1 \times 10^{31} kg) .$

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Answer:

Solution:

$λ = \frac{h}{p} a n d \frac{p^{2}}{2 m} = E$

$p = \frac{h}{λ} = \sqrt{2 m E} \Rightarrow E = \frac{h^{2}}{2 m λ^{2}}$

Substitutions the given values

$E = 8 \times 10^{- 25}$ J

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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