Physics - Modern Physics Question with Solution | TestHub

Given, slope of graph tan$\theta$= 4.12 x 10^-15V - s and charge on electron e = 1.6 x 10^-19C

   

For slope of graph$\text{tan }\theta =\frac{\text{V}}{\text{v}}$

We know that
hv = eV

$\frac{\text{V}}{\text{v}}=\frac{\text{h}}{\text{e}}$

$\therefore$$\frac{\text{h}}{\text{e}}=4\text{.}12\times 10^{-15}$

h = 1.6 x 10^-19x 4.12 x 10^-15

= 6.592 x 10^-34J - s.