Physics - Modern Physics Question with Solution | TestHub

$KE=\frac{1}{2}m{v}_{\max }^2=h\left(\nu -{\nu }_o\right)$

$K.E_{\max }=h\nu -h{\nu }_o$

$\therefore K{E}_{\mathrm{m}\mathrm{a}\mathrm{x}}$depends on frequency of incident radiation