Physics - Modern Physics Question with Solution | TestHub

$\mathrm{KE}$ of an electron in nth orbit : ${\mathrm{K}}_{\mathrm{n}}\propto \frac{1}{{\mathrm{n}}^2}$ and PE of an electron in nth orbit : ${\mathrm{U}}_{\mathrm{n}}\propto \frac{1}{{\mathrm{n}}^2}$ $\therefore$ When an electron passes from state $\mathrm{n}=2$ to $\mathrm{n}=1$ $\frac{{\mathrm{K}}_2}{{\mathrm{K}}_1}=\frac{1^2}{2^2}=\frac{1}{4}$ $\begin{array}{l}\text{ or }{\mathrm{K}}_1=4{\mathrm{K}}_2\\ \frac{{\mathrm{U}}_2}{{\mathrm{U}}_1}=\frac{{\mathrm{l}}^2}{2^2}=\frac{1}{4}\\ \text{ or }{\mathrm{U}}_1=4{\mathrm{U}}_2\end{array}$