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PhysicsModern PhysicsRadioactivityEasy2 minPYQ_2020
PhysicsEasysingle choice

The end product of the decay of 90Th232  is 82Pb208. The number ofα and β-particles emitted are respectively

Options:

Answer:
A
Solution:

Letα-particles emitted arexandβ-particles emitted arey

 90Th232 → 82Pb208  + x 2He4 + y  -1e0

On comparing the atomic number

 90=82+2x-y

or  2x-y=8           ...(i)

On comparing the mass number

 232=208 + 4x

or  x=6        

Putting the value ofxin Eq.(i), we get

y=4

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity
⏱ 2mℹ️ Source: PYQ_2020

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