Physics - Modern Physics Question with Solution | TestHub

According to Bohr’s atomic model
$mvr=\frac{nh}{2\pi }$
And the de-Broglie wavelength
$\lambda =\frac{h}{mv}$
From the above two equations we can write,$\lambda =\frac{2\pi r}{n}$
In the 2^ndexcited state
$\lambda =\frac{2\pi r}{3}$
$\therefore \mathrm{ }\mathrm{ }\lambda =\frac{2}{3}\pi \times 4.65\mathrm{ }\mathrm{ }\mathrm{Å}=9.7\mathrm{ }\mathrm{Å}$