Start Free Mock LoginAlready registered? Login here

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2018

PhysicsMediumsingle choice

The activity of a radioactive sample is measured as 9750 counts per minute at $t = 0$ and as 975 counts per minute at $t = 5$ minutes. The decay constant is approximately

Options:

Answer:

Solution:

$\frac{d N}{d t} = K N$ $9750 = K N_{0}$ $975 = K N$ Dividing (i) by (ii) $\frac{N}{N _{0}} K = \frac{1}{10} = \frac{2.303}{t} lo g \frac{N _{0}}{N} = \frac{2.303}{5} lo g 10 = 0.4606 = 0.461 per minute$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...