Physics - Modern Physics Question with Solution | TestHub

According to de-Broglie hypothesis

$\lambda =\frac{h}{p}$

Where,$h$is Planck's constant.

$\Rightarrow p=\frac{h}{\lambda }$

Given,$h=6.63\times {10}^{-34}$J-s

$\lambda =\mathrm{2 }\mathrm{\mu }\mathrm{m}=2\times {10}^{-6} \mathrm{m}$

$\therefore p=\frac{6.63\times {10}^{-34}}{2\times {10}^{-6}}$

= 3.315$\times {10}^{-28}$kg${\mathrm{m }\mathrm{s}}^{-1}$