Consider a hydrogen atom with its electron in the n t h orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV,

Question

Consider a hydrogen atom with its electron in the n t h orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n is h c = 1242 e V n m

TestHub · Accepted Answer

E P h = h c λ = 1242 90 = 13.8 e V E P h = ∆ E + ( K . E . ) 13.8 = ∆ E + 10.4 ∆ E = 3.4 e V So electron initially was in n = 2

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