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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2012

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Highly energetic electrons are bombarded on a target of an element contain ing 30 neutrons. The ratio of radii of nucleus to that of Helium nucleus is $(14)^{1/3} .$ The atomic number of nucleus will be

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$Using R = R_{0} A^{1/3} \frac{R _{1}}{R _{2}} = (\frac{A _{1}}{A _{2}})^{1/3} \frac{R}{R _{He}} = (\frac{A}{4})^{\frac{1}{3}}$ $(14)^{1/3} = (\frac{A}{4})^{\frac{1}{3}} \Rightarrow A = 56$ So, $= 56 - 30 = 26$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2012

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