Physics - Modern Physics Question with Solution | TestHub

Nuclear radius $r\propto A^{1/3}$, where $A$ is mass number $\begin{array}{rl}& r=r_0{A}^{1/3}\\ & r=r_0(27{)}^{1/3}=3r_0\\ & r_0=\frac{3.6}{3}=1.2\mathrm{fm}\end{array}$ For ${}^{64}\mathrm{Cu}$ $\begin{array}{rl}r& =r_0{A}^{1/3}\\ & =1.2\mathrm{fm}(64{)}^{1/3}\\ & =4.8\mathrm{fm}\end{array}$