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PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2012

PhysicsMediumsingle choice

The nucleus $_{n}^{m} X$ emits one $α$ particle and $2 β$ -particles. The resulting nucleus is

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Solution:

Emission of $α$ -particle decreases the mass number and the atomic number by 4 and 2 respectively. Emission of $β$ -particle increases the atomic number by 1 while the mass number remains unchanged. After the emission of the one $α$ -particle and two $β$ -particles Decreases in mass number $= 4 - 0 = 4$ Decreases in atomic number $= 2 - 2 = 0$ $∴$ The resulting the nucleus is $m - 4, X$ . i.e. the isotope of the given nucleus.

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2012

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