Physics - Modern Physics Question with Solution | TestHub

As we know, $\frac{1}{2}m{v}^2=eV$ \begin{aligned} \Rightarrow \mathrm{v} &=\sqrt{\frac{2 e V}{m}} \\ \mathrm{p} &=\mathrm{mv}=\sqrt{2 m e V} \end{aligned} Now, ${\mathrm{p}}_{\mathrm{e}}=\sqrt{2m_e\times e\times 100}$ and ${\mathrm{p}}_{\alpha }=\sqrt{4m_{\alpha }\times e\times 100}$ $\therefore \frac{p_e}{p_{\alpha }}=\sqrt{\frac{m_e}{2m_{\alpha }}}$