Physics - Modern Physics Question with Solution | TestHub

The $\alpha$-emission of ${\mathrm{S}}^{32}$ is as follows : $$\begin{array}{rl}& {}_{16}{\mathrm{S}}^{32}\to {}_{14}{\mathrm{Si}}^{28}+{}_2{\mathrm{He}}^4\\ & {}_{14}{\mathrm{Si}}^{28}\to {}_{12}{\mathrm{Mg}}^{24}+{}_2{\mathrm{He}}^4\end{array}$$ So after the emission of two $\alpha$-particle ${}_{12}{\mathrm{Mg}}^{24}$ is formed.