The decay constant of a radio isotope is λ . If A 1 and A 2 are its activities at times t 1 and t 2 respectively, the number of nuclei which have decayed during the time ( t 1 − t 2 ) NEET

Question

The decay constant of a radio isotope is $λ$ . If $A_{1}$ and $A_{2}$ are its activities at times $t_{1}$ and $t_{2}$ respectively, the number of nuclei which have decayed during the time $(t_{1} - t_{2})$ NEET 2010 (Mains)

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Answer:

C

Solution:

$A_{1} A_{2} N_{1} - N_{2} = λ N_{1} = λ N_{2} = [\frac{A _{1} - A _{2}}{λ}]$

TestHub · Accepted Answer

A 1 ​ A 2 ​ N 1 ​ − N 2 ​ ​ = λ N 1 ​ = λ N 2 ​ = [ λ A 1 ​ − A 2 ​ ​ ] ​

Physics - Modern Physics Question with Solution | TestHub

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