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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsNuclear physicsEasy2 minPYQ_2010

PhysicsEasysingle choice

The energy released by the fission of one uranium atom is $200 MeV$ . The number of fissions per second required to produce $3.2 W$ of power is (Take $1 eV = 1.6 \times 1 0^{- 19} J$ )

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Answer:

Solution:

Hints: $u = 200 MeV = 200 \times 1 0^{6} eV = 200 \times 1 0^{6} \times 1.6 \times 1 0^{- 19} J$ $E = 3.2 J$ No of fissions $= \frac{3.2}{2 \times 1.6 \times 1 0 ^{- 11}} = 1 0^{11}$

Stream:WBJEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2010

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