An arc of radius r carries charge. The linear density of charge is λ and the arc subtends an angle 3 π at the centre. What is electric potential at the centre?

Length of the arc = r θ = 3 r π Charge on the arc = 3 r π × λ ∴ Potential at centre v = r k q = 4 π ε 0 1 × 3 r π r λ = 12 ε 0 λ

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2010

PhysicsEasysingle choice

An arc of radius $r$ carries charge. The linear density of charge is $λ$ and the arc subtends an angle $\frac{π}{3}$ at the centre. What is electric potential at the centre?

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Solution:

Length of the $arc = r θ = \frac{r π}{3}$ Charge on the $arc = \frac{r π}{3} \times λ$ $∴$ Potential at centre $v$ $= \frac{k q}{r} = \frac{1}{4 π ε _{0}} \times \frac{r π}{3} \frac{λ}{r} = \frac{λ}{12 ε _{0}}$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2010

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