The electron in the hydrogen atom jumps from excited state ( n = 3 ) to its ground state ( n = 1 ) and the photons thus emitted irradiate a photosensitive material. If the work function of the materia

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The electron in the hydrogen atom jumps from excited state ( n = 3 ) to its ground state ( n = 1 ) and the photons thus emitted irradiate a photosensitive material. If the work function of the material is 5.1 eV , the stopping potential is estimated to be (the energy of the electron in n th state E n ​ = − n 2 13.6 ​ eV )NEET 2010 (Mains)

TestHub · Accepted Answer

For n = 1 , E 1 ​ = − ( 1 ) 2 13.6 ​ = − 13.6 eV and for n = 3 , E 3 ​ = − ( 3 ) 2 13.6 ​ = − 1.51 eV So, required energy E = E 3 ​ − E 1 ​ = − ( 1.51 ) − ( − 13.6 ) = 12.09 eV ∵ E = W + eV ∴ eV = E − W eV = ( 12.09 − 51 ) e = 7 volt ​

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