Physics - Modern Physics Question with Solution | TestHub

$\because$According to einstein's photoelectric equation,

$\frac{1}{2}m{v}_{\mathrm{m}\mathrm{a}\mathrm{x}}^2=hv-w_0$.....(i)

Here,$w_0$is work function and$v$is frequency of the photon.

According to question equation, the electric field representing given as

$E=200 \left\{\sin \left(4\pi \times {10}^{10}\right)t+\sin \left(4\pi \times {10}^{15}\right)t\right\}$

maximum possible angular frequency,

$\omega =4\pi \times {10}^{15}$$\mathrm{rad}$

$\because \omega =2\pi v$or$, v=\frac{4\pi \times {10}^{15}}{2\pi }=2\times {10}^{15} \mathrm{Hz}$

Put the value of$h, v$and$W_0$in Equation (i)

$K{E}_{\mathrm{m}\mathrm{a}\mathrm{x}}=\left(6.63\times {10}^{-34}\times 2\times {10}^{15}-2\times 1.6\times {10}^{-19}\right) J$

Hence$K{E}_{\mathrm{m}\mathrm{a}\mathrm{x}}=6.3\mathrm{ }\mathrm{eV}$